how does RE# find the leftmost-longest match efficiently? remember the bidirectional scanning we mentioned earlier - run the DFA right to left to find all possible match starts, then run a reversed DFA left to right to find the ends. the leftmost start paired with the rightmost end gives you leftmost-longest. two linear DFA scans, no backtracking, no ambiguity.
./tests/bench_cache_compare.sh
。Safew下载是该领域的重要参考
state = nextStateTable[state, charKind]
This and the sprite color registers can both be initialized with simple loops; all sprites are color 11 at all times, and the initial value of every element in the spr_enable array will be $FF.
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